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    BRICKWORK ANALYSIS: How to Calculate Number of Bricks, Cement, and Mortar


     BRICKWORK ANALYSIS | HOW TO CALCULATE NUMBER OF CEMENT, MORTAR AND BRICK FOR A BUILDING

    Brickwork/blockwork analysis is done for any building project, in order to determine the required quantities of the materials that contribute to the erection of the building, such as the number of bricks/blocks, quantity of mortar ie, cement and fine aggregate quantities required to make the building project.
    Today, I’ll demonstrate how to calculate the various quantities of the materials that make up the brickwork/blockwork of a building.
    What you’ll learn:
    How to calculate number of bricks
    How to calculate the volume of mortar
    How to calculate the volume of cement
    How to calculate the volume of sand
    Let us assume that the wall thickness = 9’’, wall length = 40’, and wall height = 10’



    Determine the number of bricks, cement and sand, if the size of brick is 9 x 4.5 x 3 inches, and mortar is 25% of wall.
    Solution:
    Total brick work = length x breadth x thickness of brick
                                = 40 x 10 x 9/12
                                = 300 cft.
    25% mortar = 25/100 x 300
                                   = 75 cft.
    Net brick work = total brick work – volume of mortar
                             = 300 – 75 = 225 cft.
    Number of bricks = net brick work / volume of brick
    Volume of brick = (9/12) x (4.5/12) x (3/12) = 0.0703 cft.
    Therefore, number of bricks = 225/0.0703 = 3200 bricks
    Let us include wastage which may arise due to several factors, such as breaking of bricks, some bricks being stolen, etc.
    Let’s assume that the wastage is 20%
    Hence, wastage = 20/100 x 3200 = 640 bricks
    Therefore, total number of bricks = 3200 + 640
                                                           = 3840 bricks
    Calculating for cement and sand respectively:
    Volume of mortar = 75 cft.
    Sum of ratio = 1 + 4 = 5
    Cement = 1/5 x 75 x 1.27
                  = 19.05 cft.

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